document.write( "Question 934055: solve by completing the square.\r
\n" ); document.write( "\n" ); document.write( "y^2 + 4y – 3 = 0
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Algebra.Com's Answer #567192 by mananth(16946)\"\" \"About 
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\"y%5E2%2B4y-3=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"y%5E2%2B4y=3\"\r
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\n" ); document.write( "\n" ); document.write( "third term = (1/2co-efficient of middle term)^2\r
\n" ); document.write( "\n" ); document.write( "=(1/2(4))^2\r
\n" ); document.write( "\n" ); document.write( "=4\r
\n" ); document.write( "\n" ); document.write( "\"y%5E2%2B4t%2B4+=+3%2B4\"\r
\n" ); document.write( "\n" ); document.write( "\"%28y%2B2%29%5E2=+sqrt%287%29\"\r
\n" ); document.write( "\n" ); document.write( "take the square root\r
\n" ); document.write( "\n" ); document.write( "(y+2) = +/- \"sqrt%287%29\"\r
\n" ); document.write( "\n" ); document.write( "y = -2+/-\"sqrt%287%29\"\r
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