document.write( "Question 934055: solve by completing the square.\r
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document.write( "y^2 + 4y – 3 = 0 \n" );
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Algebra.Com's Answer #567192 by mananth(16946)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "third term = (1/2co-efficient of middle term)^2\r \n" ); document.write( "\n" ); document.write( "=(1/2(4))^2\r \n" ); document.write( "\n" ); document.write( "=4\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "take the square root\r \n" ); document.write( "\n" ); document.write( "(y+2) = +/- \n" ); document.write( "\n" ); document.write( "y = -2+/- \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |