document.write( "Question 933739: True or False? Support your answer. If one score is randomly selected from a normal distribution with µ = 100 and σ = 20, the probability of obtaining a score between X = 80 and X = 120 is p = 0.3413.
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document.write( "I would appreciate just a formula, I am not sure what to do to calculate the answer.\r
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document.write( "Thank you
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document.write( "JB \n" );
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Algebra.Com's Answer #567135 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! µ = 100 and σ = 20 \n" ); document.write( "..... \n" ); document.write( "one score is randomly selected: \n" ); document.write( "P( 80 < x <120) = P( -20/20 < z < 20/20) = normalcdf(-1,1) = .6826 \n" ); document.write( "0r \n" ); document.write( "P( 80 < x <120) = P(z < 1) - P(z < -1) = .8413 - .1587 = .6826 \n" ); document.write( ".....\r \n" ); document.write( "\n" ); document.write( " For the normal distribution: Below: z = 0, z = ± 1, z= ±2 , z= ±3 are plotted. \n" ); document.write( "68.26% of the Area under the standard normal curve is between z = -1 and z = 1 \n" ); document.write( "Note: 34.13% of the Area under the standard normal curve is between z = 0 and z = 1 \n" ); document.write( "... \n" ); document.write( "Note: z = 0 (x value: the mean) 50% of the area under the curve is to the left and 50% to the right \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |