document.write( "Question 933936: A poll asked for people's opinion on whether closing local newspapers would hurt civic life; 430 of 1001 respondents said it would hurt civic life a lot.\r
\n" ); document.write( "\n" ); document.write( "A. Find the proportion of the respondents who said closing local papers would hurt civic life a lot.\r
\n" ); document.write( "\n" ); document.write( "(round to three decimal places as needed)\r
\n" ); document.write( "\n" ); document.write( "B. Find a 95% confidence interval for the population proportion who believed closing newspaper would hurt civic life a lot. Assume the poll used a simple random sample (SRS) (In fact, it used random sampling, but a more complex method than SRS\r
\n" ); document.write( "\n" ); document.write( "(, ) round to three decimal places as needed\r
\n" ); document.write( "\n" ); document.write( "C. Find an 80% confidence interval for the population proportion who believed closing newspapers would hurt civic life a lot.\r
\n" ); document.write( "\n" ); document.write( "(, ) round to three decimal places as needed\r
\n" ); document.write( "\n" ); document.write( "D. Which interval is wider?\r
\n" ); document.write( "\n" ); document.write( "Thank you
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Algebra.Com's Answer #567133 by stanbon(75887)\"\" \"About 
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A poll asked for people's opinion on whether closing local newspapers would hurt civic life; 430 of 1001 respondents said it would hurt civic life a lot.
\n" ); document.write( " A. Find the proportion of the respondents who said closing local papers would hurt civic life a lot. (round to three decimal places as needed)
\n" ); document.write( "Ans: 430/1001 = 0.430 or 430 out of 1000
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\n" ); document.write( "B. Find a 95% confidence interval for the population proportion who believed closing newspaper would hurt civic life a lot. Assume the poll used a simple random sample (SRS) (In fact, it used random sampling, but a more complex method than SRS (, ) round to three decimal places as needed
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\n" ); document.write( "p-hat = 0.43
\n" ); document.write( "ME = 1.96*sqrt[0.43*0.57/1001] = 0.031
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\n" ); document.write( "95% CI:: 0.43-0.031 < p < 0.43+0.031
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\n" ); document.write( "C. Find an 80% confidence interval for the population proportion who believed closing newspapers would hurt civic life a lot.
\n" ); document.write( " (, ) round to three decimal places as needed
\n" ); document.write( "ME:: 1.2820*sqrt[0.43*0.57/1001] = 0.02
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\n" ); document.write( "80% CI: 0.43-0.02 < p < 0.43+0.02
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\n" ); document.write( "D. Which interval is wider?
\n" ); document.write( "95% CI is wider than 80% CI.
\n" ); document.write( "The more confidence you want, the wider the CI must be.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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