document.write( "Question 933890: a) an experiment measures eye contact of a control group of people, during a 5 minute interval. What is the probability that a randomly selected person makes eye contact for >230 seconds which is the mean for paranoid schizophrenics, during the five minute interval? Assume times are normally distributed with σ= 55 sec, μ= 184 seconds. \r
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document.write( "b) what is the value that separates off the lowest 10% of the eye contact times, from the upper 90%? \n" );
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Algebra.Com's Answer #567128 by ewatrrr(24785) You can put this solution on YOUR website! μ= 184 seconds, σ= 55 sec. \n" ); document.write( "..... \n" ); document.write( "Person selected: \n" ); document.write( "P( x > 230) = P(z > 46/55) = normalcdf(46/55, 100) = .2015 0r 20.15% \n" ); document.write( "...... \n" ); document.write( "P( .10 < x < .90) = P( -1.2816 < z < 1.2816) = normalcdf(-1.2816, 1.2816) = .8000 0r 80% \n" ); document.write( "......... \n" ); document.write( " Using a TI calculator 0r similarly a Casio fx-115 ES plus \n" ); document.write( ".. \n" ); document.write( "Recommend Using stattrek.com to check Results \n" ); document.write( "until You are familiar with Using Your Calculator. \n" ); document.write( " \n" ); document.write( " |