document.write( "Question 79040: help me please i am able to do + but not -
\n" ); document.write( "sqrt\"x-1\"=x-3
\n" ); document.write( "

Algebra.Com's Answer #56709 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
sqrt\"x-1\"=x-3
\n" ); document.write( "Square both sides to get:
\n" ); document.write( "x-1=(x-3)^2
\n" ); document.write( "x-1=x^2-6x+9
\n" ); document.write( "x^2-7x+10=0
\n" ); document.write( "Factor to get:
\n" ); document.write( "(x-5)(x-2)=0
\n" ); document.write( "x=5 or x=2
\n" ); document.write( "-------------------------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );