document.write( "Question 78860: d..ch5\r
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\n" ); document.write( "A plane took 1 hour longer to travel 560miles on the first portion of a flight than it took to fly 480miles on the second portion. If the speed was the same for each portion , what was the flying time for the second part of the trip?\r
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Algebra.Com's Answer #56707 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A plane took 1 hour longer to travel 560 miles on the first portion of a flight than it took to fly 480 miles on the second portion. If the speed was the same for each portion , what was the flying time for the second part of the trip?
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\n" ); document.write( "Let t = time of the 2nd portion (480 mi)
\n" ); document.write( "Then (t+1) = time of the 560 mi portion:
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\n" ); document.write( "The speed is the same on both portions, write an equation from this fact:
\n" ); document.write( "s = distance/time
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\n" ); document.write( "560 mi speed = 480 mi speed
\n" ); document.write( "\"560%2F%28%28t%2B1%29%29\" = \"480%2Ft\"
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\n" ); document.write( "Cross multiply and you have:
\n" ); document.write( "560t = 480(t+1)
\n" ); document.write( "560t = 480t + 480
\n" ); document.write( "560t - 480t = 480
\n" ); document.write( "80t = 480
\n" ); document.write( "t = 480/80
\n" ); document.write( "t = 6 hrs
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\n" ); document.write( "Check solution by finding the speed, which should be the same:
\n" ); document.write( "560/7 = 80
\n" ); document.write( "480/6 = 80
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