document.write( "Question 933810: A rowing team rowing with the current traveled 40 km in 4 h. Rowing against the current, the team rowed 8 km in the same amount of time. Find the rate of the rowing team in calm water and the rate of the current. \n" ); document.write( "
Algebra.Com's Answer #567060 by mananth(16946)\"\" \"About 
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boat speed =x km
\n" ); document.write( "current speed =y km
\n" ); document.write( "against current 4 hours
\n" ); document.write( "with current 4 hours
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\n" ); document.write( "Distance against 8 miles distance with 40 km
\n" ); document.write( "t=d/r against current -
\n" ); document.write( "8.00 / ( x - y )= 4.00
\n" ); document.write( "4.00 ( x - y ) = 4.00
\n" ); document.write( "4.00 x - 4.00 y = 8.00 ....................1
\n" ); document.write( "
\n" ); document.write( "40.00 / ( x + y )= 4.00
\n" ); document.write( "4.00 ( x + y ) = 40.00
\n" ); document.write( "4.00 x + 4.00 y = 40.00 ...............2
\n" ); document.write( "Multiply (1) by 4.00
\n" ); document.write( "Multiply (2) by 4.00
\n" ); document.write( "we get
\n" ); document.write( "16.00 x + -16.00 y = 32.00
\n" ); document.write( "16.00 x + 16.00 y = 160.00
\n" ); document.write( "32.00 x = 192.00
\n" ); document.write( "/ 32.00
\n" ); document.write( "x = 6.00 km/h
\n" ); document.write( "
\n" ); document.write( "plug value of x in (1) y
\n" ); document.write( "4.00 x -4.00 y = 8.00
\n" ); document.write( "24.00 -4.00 -24.00 = 8.00
\n" ); document.write( "-4.00 y = 8.00
\n" ); document.write( "-4.00 y = -16.00 km/h
\n" ); document.write( " y = 4.00
\n" ); document.write( "boat speed 6.00 km/h
\n" ); document.write( "current speed 4.00 km/h
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\n" ); document.write( "m.ananth@hotmail.ca
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