document.write( "Question 933777: You and a friend are 400 m away from school, walking together toward home at a speed of 1.9 m/s. Suddenly, you remember that you remember that you need to bring your physics binder! You turn around and run (with a speed of 4.2 m/s) back to school, while you friend continues to walk. Then, you run back toward your friend to catch back up. How long are you running (total) before you catch back up with your friend? \n" ); document.write( "

Algebra.Com's Answer #567059 by mananth(16946) $\"\"$ $\"About$

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You run back to school at 4.2m/s
\n" ); document.write( "distance = 400 m\r
\n" ); document.write( "\n" ); document.write( "time taken by you to reach school = 400/4.2= 95.2 seconds\r
\n" ); document.write( "\n" ); document.write( "during that time your friend is walking at 1.9 m/s
\n" ); document.write( "so he has walked ahead 1.9*95.2=180.9 m\r
\n" ); document.write( "\n" ); document.write( "when you are at school he is 400 + 181 = 581 m ahead of you\r
\n" ); document.write( "\n" ); document.write( "catch time = catchup distance /catch up rate\r
\n" ); document.write( "\n" ); document.write( "581/(4.2-19)\r
\n" ); document.write( "\n" ); document.write( "581/2.3= 252.6 sec\r
\n" ); document.write( "\n" ); document.write( "so you run 95.2 sec + 252.6 sec\r
\n" ); document.write( "\n" ); document.write( "=\r
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