document.write( "Question 933794: A motorboat traveling with the current went 48 mi in 2 h. Traveling against the current, it took 3 h to travel the same distance. Find the rate of the boat in calm water and the rate of the current. \n" ); document.write( "
Algebra.Com's Answer #567036 by mananth(16946)\"\" \"About 
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boat speed =x mph
\n" ); document.write( "current speed =y mph
\n" ); document.write( "against current 3 hours
\n" ); document.write( "with current 2 hours
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\n" ); document.write( "Distance against 48 miles distance with 48 miles
\n" ); document.write( "t=d/r against current -
\n" ); document.write( "48.00 / ( x - y )= 3.00
\n" ); document.write( "3.00 ( x - y ) = 2.00
\n" ); document.write( "3.00 x - 3.00 y = 48.00 ....................1
\n" ); document.write( "
\n" ); document.write( "48.00 / ( x + y )= 2.00
\n" ); document.write( "2.00 ( x + y ) = 48.00
\n" ); document.write( "2.00 x + 2.00 y = 48.00 ...............2
\n" ); document.write( "Multiply (1) by 2.00
\n" ); document.write( "Multiply (2) by 3.00
\n" ); document.write( "we get
\n" ); document.write( "6.00 x + -6.00 y = 96.00
\n" ); document.write( "6.00 x + 6.00 y = 144.00
\n" ); document.write( "12.00 x = 240.00
\n" ); document.write( "/ 12.00
\n" ); document.write( "x = 20.00 mph
\n" ); document.write( "
\n" ); document.write( "plug value of x in (1) y
\n" ); document.write( "3.00 x -3.00 y = 48.00
\n" ); document.write( "60.00 -3.00 -60.00 = 48.00
\n" ); document.write( "-3.00 y = 48.00
\n" ); document.write( "-3.00 y = -12.00 mph
\n" ); document.write( " y = 4.00
\n" ); document.write( "boat speed 20.00 mph
\n" ); document.write( "current speed 4.00 mph
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\n" ); document.write( "m.ananth@hotmail.ca
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