document.write( "Question 933763: Jared wanted to find three consecutive even integers whose sum was 4 times the first of those integers. He let k represent the first integer, then wrote and solved this equation: k+ (k+1) + (k+2) = 4k. Did he get the correct answer? Complete the explanation. \r
\n" ); document.write( "\n" ); document.write( "Jared did not get the correct answer. The solution to his equation is k = ____, giving ___,___, and ___ as the three integers. However 3 and 5 are not even integers. He should have used the equation k + (k + ___) + (k+___) = 4k, which gives k =___ and the correct answer ___,___,___.
\n" ); document.write( "Help would be much appreciated
\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #567025 by richard1234(7193) $\"\"$ $\"About$

You can put this solution on YOUR website!
Instead of k, k+1, k+2, you should use k, k+2, k+4 with the constraint that k is even (i.e. if you return an odd integer for k, or a non-integer, then return no solution).\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "k + (k+2) + (k+4) = 4k
\n" ); document.write( "3k + 6 = 4k
\n" ); document.write( "k = 6\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Indeed, 6+8+10 = 4*6. \n" ); document.write( "

\n" );