document.write( "Question 933333: If a,b,c,d are in H.P., prove that ab+bc+cd = 3ad \n" ); document.write( "
Algebra.Com's Answer #566991 by Edwin McCravy(20056)\"\" \"About 
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If a,b,c,d are in H.P., prove that ab+bc+cd = 3ad
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document.write( "Then the reciprocals  are in AP.\r\n" );
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document.write( "Let 2k = the common difference of the AP\r\n" );
document.write( "Let m = the mean of the four terms of the AP \r\n" );
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document.write( "[Note: m is the number half-way between the middle two terms, so 1/b is k \r\n" );
document.write( "less than m and 1/a is 2k less than 1/b or 3k less than m.  Similarly 1/c\r\n" );
document.write( "is k more than m and 1/d is 2k more than 1/c or 3k more than m.)\r\n" );
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document.write( "So \"1%2Fb=m-k\", \"1%2Fa=m-3k\", \"1%2Fc=m%2Bk\", \"1%2Fd=m%2B3k\"\r\n" );
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document.write( "and \"b=1%2F%28m-k%29\", \"a=1%2F%28m-3k%29\", \"c=1%2F%28m%2Bk%29\", \"d=1%2F%28m%2B3k%29\"\r\n" );
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document.write( "\"ab%2Bbc%2Bcd\"\"%22%22=%22%22\"\"%22%22=%22%22\"\r\n" );
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document.write( "Get LCD:\r\n" );
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document.write( "\"%22%22=%22%22\"\r\n" );
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document.write( "\"%22%22=%22%22\"\r\n" );
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document.write( "\"%283m%5E2-3k%5E2%29%2F%28%28m-3k%29%28m-k%29%28m%2Bk%29%28m%2B3k%29%29\"\"%22%22=%22%22\"\r\n" );
document.write( "\r\n" );
document.write( "\"%283%28m%5E2-k%5E2%29%29%2F%28%28m-3k%29%28m-k%29%28m%2Bk%29%28m%2B3k%29%29\"\"%22%22=%22%22\"\r\n" );
document.write( "\r\n" );
document.write( "\"%283%28m-k%29%28m%2Bk%29%29%2F%28%28m-3k%29%28m-k%29%28m%2Bk%29%28m%2B3k%29%29\"\"%22%22=%22%22\"\r\n" );
document.write( " \r\n" );
document.write( "\"%22%22=%22%22\"\r\n" );
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document.write( "\"3%2F%28%28m-3k%29%28m%2B3k%29%29\"\"%22%22=%22%22\"\r\n" );
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document.write( "\"3%281%2F%28m-3k%29%29%281%2F%28m%2B3k%29%29\"\"%22%22=%22%22\"\r\n" );
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document.write( "\"3ad\"\r\n" );
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document.write( "Edwin
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