document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=933690>Question 933690</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How long will it take for $9800 to grow to $14,500 at an interest rate of 6.1% if the interest is compounded continuously? Round the number of years to the nearest hundredth. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #566973 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=566973\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A = P e ^(rt)<BR>\n" );
document.write( "A/P = e ^(rt)<BR>\n" );
document.write( "ln(A/P) = rt<BR>\n" );
document.write( "ln(A/P)/r = t<BR>\n" );
document.write( "ln(14500/9800)/.061 = t = 6.42yr (Rounded to the nearest hundredth) </SPAN>\n" );
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