document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=79035>Question 79035</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Factor completely. <BR>\n" );
document.write( "b^2 – ab – 6a^2<BR>\n" );
document.write( "I got this answer this time is it right?<BR>\n" );
document.write( "(b – 6a)(b + a)<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #56697 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=56697\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> b^2 – ab – 6a^2<BR>\n" );
document.write( "You are looking at the 1st and 3rd terms and forgetting about the middle term.<BR>\n" );
document.write( "Think of two numbers whose product is -6 and whose sum is -1.<BR>\n" );
document.write( "The numbers are -3 and +2<BR>\n" );
document.write( "Replace the middle term, -ab, with  -3ab+2ab<BR>\n" );
document.write( "b^2-3ab+2ab-6a^2<BR>\n" );
document.write( "Factor the 1st two and the last two terms separately<BR>\n" );
document.write( "b(b-3a)+2a(b-3a)<BR>\n" );
document.write( "Factor again to get:<BR>\n" );
document.write( "(b-3a)(b+2a)<BR>\n" );
document.write( "Check this by multiply it out.<BR>\n" );
document.write( "==================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );