document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=933683>Question 933683</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the lengths of two sides of a triangle are 8cm and 10cm identify the range of the possible lengths for the third side? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #566961 by </B><A HREF=/tutors/aboutme.mpl?userid=KMST><B>KMST(5328)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=KMST><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=KMST><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=566961\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2 < 3rd side length < 12<BR>\n" );
document.write( "The length of any side has to ne less than the sum of the lengths of the other 2 sides because a straight line (side) is the shortest distance between 2 points/vertices.<BR>\n" );
document.write( "If you call the 3rd length x,<BR>\n" );
document.write( "x < 10+2 , so x < 12<BR>\n" );
document.write( "and<BR>\n" );
document.write( "x + 8 > 10 , so x > 10-8 , which means x > 2 . </SPAN>\n" );
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