document.write( "Question 933599: Can someone explain to me how the right triangle trigonometric functions are related to the unit circle trigonometric functions? I am finding this very confusing and the textbook is complicating things for me, not helping. Thank you so much in advance! \n" ); document.write( "
Algebra.Com's Answer #566949 by stanbon(75887)\"\" \"About 
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Can someone explain to me how the right triangle trigonometric functions are related to the unit circle trigonometric functions? I am finding this very confusing and the textbook is complicating things for me, not helping. Thank you so much in advance!
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\n" ); document.write( "Draw a circle.
\n" ); document.write( "Let the radius be 1.
\n" ); document.write( "Pick a point on the circle somewhere between 0 and 90 degrees
\n" ); document.write( "Let the coordinates of that point be P(x,y)
\n" ); document.write( "Draw a vertical line segment from P to the x-axis
\n" ); document.write( "You now have a right triangle with base = x, height = y, hypotenuse = 1.
\n" ); document.write( "The angle at the origin is \"t\".
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\n" ); document.write( "sin(t) = opp/hyp = y/1 = y
\n" ); document.write( "cos(t) = adj/hyp = x/1 = x
\n" ); document.write( "tan(t) = opp/adj = y/x
\n" ); document.write( "----
\n" ); document.write( "csc(t) = hyp/opp = 1/y
\n" ); document.write( "sec(t) = hyp/adj = 1/x
\n" ); document.write( "cot(t) = adj/opp = x/y
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\n" ); document.write( "Note: All above applies no matter when P is on the circle.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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