document.write( "Question 933555: Find the value of m so that dividing x^4-mx^3-2x^2+(3m-5)x+m by (x-m) gives a remainder of 5. \n" ); document.write( "
Algebra.Com's Answer #566876 by mananth(16946)\"\" \"About 
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x^4-mx^3-2x^2+(3m-5)x+m by (x-m) gives a remainder of 5.\r
\n" ); document.write( "\n" ); document.write( "substitute x=m\r
\n" ); document.write( "\n" ); document.write( "m^4-m^4-2m^2+3m^2-5m+m \r
\n" ); document.write( "\n" ); document.write( "m^2-4m =5\r
\n" ); document.write( "\n" ); document.write( "m^2-4m-5=0\r
\n" ); document.write( "\n" ); document.write( "m^2--5m+m-5=0\r
\n" ); document.write( "\n" ); document.write( "m(m-5)+1(m-5)=0\r
\n" ); document.write( "\n" ); document.write( "(m-5)(m+1)=0
\n" ); document.write( "m=5 OR 1
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