document.write( "Question 933531: Find the lengths of the three sides of the right triangle if the two legs measure x feet, (x+14) feet, respectively, and the hypotenuse measure (x+16) feet. \n" ); document.write( "

Algebra.Com's Answer #566869 by mananth(16946) $\"\"$ $\"About$

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x^2+(x+14)^2 = (x+16)^2 by Pythagoras theorem\r
\n" ); document.write( "\n" ); document.write( "x^2+x^2+28x+196 = x^2+32x+256\r
\n" ); document.write( "\n" ); document.write( "simplify\r
\n" ); document.write( "\n" ); document.write( "x^2-4x-60=0\r
\n" ); document.write( "\n" ); document.write( "x^2-10x+6x-60=0\r
\n" ); document.write( "\n" ); document.write( "x(x-10)+6(x-10)=0\r
\n" ); document.write( "\n" ); document.write( "(x-6)(x-10)=0
\n" ); document.write( "x= 6 OR 10
\n" ); document.write( "check which is applicable
\n" ); document.write( "x=6
\n" ); document.write( "x+14=20
\n" ); document.write( "x+16=22\r
\n" ); document.write( "\n" ); document.write( "6^2+20^2=36+400 = 436
\n" ); document.write( "22^2= 441
\n" ); document.write( "x=6 is not applicable\r
\n" ); document.write( "\n" ); document.write( "substitute the value of x \r
\n" ); document.write( "\n" ); document.write( "10^2+24^2=676\r
\n" ); document.write( "\n" ); document.write( "26^2=676\r
\n" ); document.write( "\n" ); document.write( "so the sides are 10,24 & 26 \n" ); document.write( "

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