document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=933518>Question 933518</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much of an 18% solution of sulfuric acid should be added to 380ml of a 10% solution to obtain a 15% solution?\r<BR>\n" );
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document.write( "Please help - I'm totally stumped!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #566850 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=566850\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ---	percent	----------------	Amount									<BR>\n" );
document.write( "acid type I	10	----------------			380	ml						<BR>\n" );
document.write( "acid type II	18	----------------			x	ml						<BR>\n" );
document.write( "Mixture	15	----------------	380	+	x	ml						<BR>\n" );
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document.write( "10	*	380	+	18	x	=	15	(	380	+	x	)<BR>\n" );
document.write( "3800	+	18	x	=	5700	+	15	x				<BR>\n" );
document.write( "18	x		-15	x	=	-3800	+	5700				<BR>\n" );
document.write( "3	x	=	1900									<BR>\n" );
document.write( "/	3											<BR>\n" );
document.write( "x	=	633.33		ml	acid type II							<BR>\n" );
document.write( "												<BR>\n" );
document.write( "m.ananth@hotmail.ca												<BR>\n" );
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