document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=933379>Question 933379</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the area of a rectangle is 52 and perimeter is 34 and length=width*2+5 what is length and width </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #566801 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=566801\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if the area of a rectangle is 52 and perimeter is 34 and length=width*2+5 what is length and width<BR>\n" );
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document.write( "Area = L*W = 52<BR>\n" );
document.write( "Perimeter = 2L + 2W = 34 --> L + W = 17<BR>\n" );
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document.write( "Try pairs of factors of 52 (there aren't many).<BR>\n" );
document.write( "Find a pair with a sum of 17.<BR>\n" );
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