document.write( "Question 932351: graph the parabola and identify the vertex, focus, directrix: x^2+16y=0 \n" ); document.write( "

Algebra.Com's Answer #566728 by lwsshak3(11628) $\"\"$ $\"About$

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graph the parabola and identify the vertex, focus, directrix: x^2+16y=0
\n" ); document.write( "This is a parabola that opens downward.
\n" ); document.write( "Its basic equation: (x-h)^2=4p(y-k), (h,k)=coordinates of vertex
\n" ); document.write( "For given parabola:
\n" ); document.write( "x^2=-16y
\n" ); document.write( "vertex: (0,0)
\n" ); document.write( "axis of symmetry: x=0 or y-axis
\n" ); document.write( "4p=16
\n" ); document.write( "p=4
\n" ); document.write( "focus:(0,-4) (p-units below vertex on the axis of symmetry)
\n" ); document.write( "directrix:y=4 (p-units above vertex on the axis of symmetry)
\n" ); document.write( "see graph below:
\n" ); document.write( " $\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+-x%5E2%2F16%29+\"$ \n" ); document.write( "

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