document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=933242>Question 933242</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm struggling with rewriting sin(x-4pi/3). I know it equals sinxcos4pi/3-sin4pi/3cosx and that cos4pi/3 equals (-1/2) and that sin 4pi/3 equals (-sqrt3/2)  but I don't know where to go from there. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #566722 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=566722\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I'm struggling with rewriting sin(x-4pi/3). I know it equals sinxcos4pi/3-sin4pi/3cosx and that cos4pi/3 equals (-1/2) and that sin 4pi/3 equals (-sqrt3/2) but I don't know where to go from there.<BR>\n" );
document.write( "***<BR>\n" );
document.write( "sin(x-4&#960;/3)<BR>\n" );
document.write( "=sinxcos(4&#960;/3)-cosxsin(4&#960;/3)<BR>\n" );
document.write( "=sinx*(-1/2)-cosx*(-&#8730;3/2)<BR>\n" );
document.write( "=-sinx/2+&#8730;3cosx/2<BR>\n" );
document.write( "=(sinx+&#8730;3cosx)/2 </SPAN>\n" );
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