document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=933275>Question 933275</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help! I've tried several times to figure out this question and it just flusters me. \"What are the sets of consecutive numbers that add up to 315?\" I have found one and it is 104+105+106=315 and there are 11 total ways. I understand you are busy but i would really appriciate if you could help me out. Thank you.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #566717 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=566717\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \"What are the sets of consecutive numbers that add up to 315?\" I have found one and it is 104+105+106=315 and there are 11 total ways.<BR>\n" );
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document.write( "It's the factors of 315<BR>\n" );
document.write( "3 is one.<BR>\n" );
document.write( "315/3 = 105, the middle # of the three --> 104, 105, 106<BR>\n" );
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document.write( "Then 5.<BR>\n" );
document.write( "315/5 = 63, the middle number --> 61, 62, 63, 64 & 65<BR>\n" );
document.write( "then 7, 9, 15, 21, 35, 45, 63, 105 and 315. </SPAN>\n" );
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