document.write( "Question 933145: e^[3ln(x^2)-2ln(x)]=ln(e^16), I can not do that, help me please. Need to find exact solution. \n" ); document.write( "
Algebra.Com's Answer #566646 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"e%5E%283ln%28x%5E2%29-2ln%28x%29%29=ln%28e%5E16%29\"...........since \"ln%28e%5E16%29=16\"\r
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\n" ); document.write( "\n" ); document.write( "\"e%5E%28ln%28%28x%5E2%29%5E3%29-ln%28x%5E2%29%29=16\"\r
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\n" ); document.write( "\n" ); document.write( "\"e%5E%28ln%28x%5E6%29-ln%28x%5E2%29%29=16\"\r
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\n" ); document.write( "\n" ); document.write( "\"e%5E%28ln%28x%5E6%2F%28x%5E2%29%29%29=16\" ....-> in case you can't see, here is e^(ln(x^6/(x^2)))=16\r
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\n" ); document.write( "\n" ); document.write( "\"e%5E%28ln%28x%5E4%29%29=16\" ................\"e%5E%28ln%28x%5E4%29%29=x%5E4+\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E4=16\" \r
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\n" ); document.write( "\n" ); document.write( "\"x=root%284%2C16%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=root%284%2C2%5E4%29\"\r
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\n" ); document.write( "\n" ); document.write( "solutions:\r
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\n" ); document.write( "\n" ); document.write( "\"x=2\" or \"x=-2\"\r
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