document.write( "Question 933107: if ram walks from his house at 5km/h he reaches school 5 min early
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document.write( "and if he walks 4 km/h he reaches 5 min late . waht is the actual distance between ram house and school
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Algebra.Com's Answer #566643 by ptfile(81)![]() ![]() You can put this solution on YOUR website! Let 5km/h = the ram's rate at faster pace \n" ); document.write( " 4km/h = the ram's rate at slower pace\r \n" ); document.write( "\n" ); document.write( "If ram walks from his house at 5km/h he reaches school 5 min early \n" ); document.write( "and if he walks 4 km/h he reaches 5 min late. \n" ); document.write( "5(x-5)= 4(x+5) \n" ); document.write( "5x-25 = 4x+20 \n" ); document.write( " x = 45\r \n" ); document.write( "\n" ); document.write( "substitute x with 45 \n" ); document.write( "45-5=40 \n" ); document.write( "45+5=50\r \n" ); document.write( "\n" ); document.write( "Distance = (rate)(time) \n" ); document.write( " d = (5)(40) \n" ); document.write( " d = 200km \n" ); document.write( " d = (4)(50) \n" ); document.write( " d = 200km\r \n" ); document.write( "\n" ); document.write( "The distance ram travels from its house going to the school is 200km. \r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |