document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=926557>Question 926557</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a certain number is added to both the numerator<BR>\n" );
document.write( "and denominator of the fraction 7<BR>\n" );
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document.write( "9<BR>\n" );
document.write( ", the result is 5<BR>\n" );
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document.write( "7<BR>\n" );
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document.write( "Find the number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #566619 by </B><A HREF=/tutors/aboutme.mpl?userid=ptfile><B>ptfile(81)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptfile><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptfile><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=566619\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = the number added to numerator and denominator\r<BR>\n" );
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document.write( "If a certain number is added to both the numerator<BR>\n" );
document.write( "and denominator of the fraction 7/9, the result is 5/7.\r<BR>\n" );
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document.write( "(x+7)/(x+9) = 5/7<BR>\n" );
document.write( " 7(x+7) = 5(x+9)<BR>\n" );
document.write( " 7x+49  = 5x+45<BR>\n" );
document.write( "   2x   = -4<BR>\n" );
document.write( "    x   = -2\r<BR>\n" );
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document.write( "The number is -2.\r<BR>\n" );
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document.write( "Check<BR>\n" );
document.write( "(-2+7)/(-2+9)= 5/7<BR>\n" );
document.write( "         5/7 = 5/7 </SPAN>\n" );
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