document.write( "Question 932887: Let A and B be two events, with probabilities P(A) = 0,6, and P(B) =
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document.write( "0,2. Calculate the following probabilities: P(A' ), P(AUB), P(A intersection B), P(AIB),
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document.write( "P(BIA), if:
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document.write( "(1) A and B are mutually exclusive (disjoint).
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document.write( "(2) A and B are independent.
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document.write( "(B) If A, and B are two events, where P(A) = k, P(AUB) = 0,5, P(B) = 0,33:
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document.write( "(1) Find k, if A and B are independent.
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document.write( "(2) Find k, if A and B are mutually exclusive (disjoint). \n" );
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Algebra.Com's Answer #566456 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! P(A) = 0.6, and P(B) =0.2 \n" ); document.write( "(1) A and B are mutually exclusive (disjoint). \n" ); document.write( "P(A' ) = .4 \n" ); document.write( "P(AUB) = .8 \n" ); document.write( "P(AᑎB) = 0 \n" ); document.write( "P(A|B) = .6 \n" ); document.write( "(2) A and B are independent. \n" ); document.write( "P(A' ) = .4 \n" ); document.write( "P(AUB) = .8 \n" ); document.write( "P(AᑎB) = .4*.8 \n" ); document.write( "P(A|B) = .6 \n" ); document.write( "......... \n" ); document.write( "P(A) = k, P(AUB) = 0.5, P(B) = 0.33 \n" ); document.write( "mutually exclusive (disjoint). \n" ); document.write( "P(AUB) = P(A) + P(B) \n" ); document.write( ".5 = k + .33 \n" ); document.write( ".17 = k\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |