document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=932883>Question 932883</A>: <I><SPAN STYLE=\"word-break: break-all;\"> For each of the following, prove that the line is a tangent to the parabola, and find the point of contact.\r<BR>\n" );
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document.write( "y=x-1/4 and y=x^2\r<BR>\n" );
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document.write( "I had simplified that to x^2-x+1/4\r<BR>\n" );
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document.write( "However, I cannot factorise that equation....in that form. I know that it MUST be a tangent; as when I used the discriminant, i.e. b^2-4ac; the answer was exactly 0. \r<BR>\n" );
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document.write( "Previously, with other questions I was able to clearly identify the value of x, by factorising; then, subsituting the value of x derived in this manner, into either of the original equations to find Y.\r<BR>\n" );
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document.write( "However, because I can't factorise here, I can't do that so am at a dead end.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #566453 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=566453\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x^2-x+1/4 = (x - (1/2))^2<BR>\n" );
document.write( "x = 1/2 and y = 1/4 therefore<BR>\n" );
document.write( "(1/2, 1/4) is the point of tangency  </SPAN>\n" );
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