document.write( "Question 932840: THE PERIMETER IS 116. AND THE WIDTH IS 45% OF THE LENGTH. WHAT ARE THE LENGTH AND WIDTH? \n" ); document.write( "
Algebra.Com's Answer #566410 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
THE PERIMETER IS 116. AND THE WIDTH IS 45% OF THE LENGTH. WHAT ARE THE LENGTH AND WIDTH?
\n" ); document.write( "----
\n" ); document.write( "Perimeter = 2(length + width)
\n" ); document.write( "-------
\n" ); document.write( "116 = 2(L + 0.45L)
\n" ); document.write( "58 = 1.45L
\n" ); document.write( "L = 58/1.45
\n" ); document.write( "Length = 40
\n" ); document.write( "----
\n" ); document.write( "Width = 0.45L = 0.45*40 = 18
\n" ); document.write( "----------------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );