document.write( "Question 932840: THE PERIMETER IS 116. AND THE WIDTH IS 45% OF THE LENGTH. WHAT ARE THE LENGTH AND WIDTH? \n" ); document.write( "
Algebra.Com's Answer #566410 by stanbon(75887) ![]() You can put this solution on YOUR website! THE PERIMETER IS 116. AND THE WIDTH IS 45% OF THE LENGTH. WHAT ARE THE LENGTH AND WIDTH? \n" ); document.write( "---- \n" ); document.write( "Perimeter = 2(length + width) \n" ); document.write( "------- \n" ); document.write( "116 = 2(L + 0.45L) \n" ); document.write( "58 = 1.45L \n" ); document.write( "L = 58/1.45 \n" ); document.write( "Length = 40 \n" ); document.write( "---- \n" ); document.write( "Width = 0.45L = 0.45*40 = 18 \n" ); document.write( "---------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |