document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=932537>Question 932537</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If nine hens can lay six eggs in two days, how many hens would be needed to lay 24 eggs in three days?<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #566275 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=566275\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x= number of hens required to lay 24 eggs in 3 day<BR>\n" );
document.write( "then x hens lays eggs at the rate of 24/3=8 eggs per day<BR>\n" );
document.write( "9 hens lays at the rate of 6/2 =3 eggs per day<BR>\n" );
document.write( "1 hen lays at the rate of 2/9=1/3 egg per day<BR>\n" );
document.write( "From here, we can go two ways:<BR>\n" );
document.write( "(1) set up a ratio:<BR>\n" );
document.write( "x/8=9/3<BR>\n" );
document.write( "3x=72<BR>\n" );
document.write( "x=24---number of hens needed<BR>\n" );
document.write( "(2) Another way:<BR>\n" );
document.write( "1/3 egg/day(x)hens=8 eggs/day, or<BR>\n" );
document.write( "(1/3)x=8<BR>\n" );
document.write( "x=24---hens needed\r<BR>\n" );
document.write( "\n" );
document.write( "Hope this helps---ptaylor<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );