document.write( "Question 931537: Solve 1 power 4/ (1 x 3) + 2 power 4 /(3 x 5) +3 power 4/(5 x 7)………………n power 4/(2n-1)(2n+1)\r
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Algebra.Com's Answer #566272 by Edwin McCravy(20056)\"\" \"About 
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1 power 4/ (1 x 3) + 2 power 4 /(3 x 5) +3 power 4/(5 x 7)………………n power 4/(2n-1)(2n+1)
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document.write( "\"sum%28k%5E4%2F%28%282k-1%29%282k%2B1%29%29%2Ck=1%2Cn%29\"\r\n" );
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document.write( "We break \"k%5E4%2F%28%282k-1%29%282k%2B1%29%29\"\r\n" );
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document.write( "into partial fractions, first by writing it as \r\n" );
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document.write( "Then break \"1%2F%28%282k-1%29%282k%2B1%29%29\" into partial fractions, getting\r\n" );
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document.write( "\"expr%281%2F2%29%281%2F%282k-1%29-1%2F%282k%2B2%29%29\"\r\n" );
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document.write( "Then that's telescoping series.  Then use the sum of squares formula\r\n" );
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document.write( "and put it altogether and you end up with the expression for the sum as\r\n" );
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document.write( "\"%28n%28n%5E3%2B2n%5E2%2B2n%2B1%29%29%2F%286%282n%2B1%29%29\"\r\n" );
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document.write( "Edwin
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