document.write( "Question 932605: Of 116 randomly selected adults, 34 were found to have high blood pressure. Find a 98% confidence interval for the percentage of adults that have high blood pressure. \n" ); document.write( "
Algebra.Com's Answer #566242 by ewatrrr(24785) You can put this solution on YOUR website! p(HBP) = 34/116 = .2931 \n" ); document.write( "ME = 2.326sqrt((.2931)(.7069)/116) = .0423 \n" ); document.write( "CI: = .2931 ± .0447 \n" ); document.write( "(25.08%, 33.54%) \n" ); document.write( "round as directed\r \n" ); document.write( "\n" ); document.write( "..... \n" ); document.write( " CI z = value \n" ); document.write( "90% z =1.645 \n" ); document.write( "92% z = 1.751 \n" ); document.write( "95% z = 1.96 \n" ); document.write( "98% z = 2.326 \n" ); document.write( "99% z = 2.576 \n" ); document.write( " \n" ); document.write( " |