document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=932598>Question 932598</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is 5 times its width. If its area is 125 square feet, what is its dimensions? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #566230 by </B><A HREF=/tutors/aboutme.mpl?userid=jack.wang5><B>jack.wang5(5)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jack.wang5><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=566230\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let A = area = L W, W = width, L = length = 5W. \r<BR>\n" );
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document.write( "Therefore A = L W = 5 W W = 5 W^2 , so A = 5 W^2.\r<BR>\n" );
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document.write( "Solve W , and thus W = sqrt(A/5).\r<BR>\n" );
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document.write( "Since A = 125, therefore W = sqrt(125/5) = 5. </SPAN>\n" );
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