document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=932594>Question 932594</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of a parabola that has a Minimum turning point at (2,-5).\r<BR>\n" );
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document.write( "I am totally confused how to do this.\r<BR>\n" );
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document.write( ".I looked up the answer; which is listed as being y=x^2-4x-1\r<BR>\n" );
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document.write( "I tried to complete the square; so; (x-2)^2--2]-1\r<BR>\n" );
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document.write( "But that would give me a y value of 11\r<BR>\n" );
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document.write( "So x; seems to correct...but not sure if that is a fluke, \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #566219 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=566219\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the equation of a parabola that has a Minimum turning point at (2,-5). <BR>\n" );
document.write( "y = a(x-2)^2 - 5  for a = 1 (which is one such parabola)<BR>\n" );
document.write( "y = (x-2)^2 - 5<BR>\n" );
document.write( "y = x^2 -4x + 4 - 5<BR>\n" );
document.write( "y = x^2 - 4x - 1<BR>\n" );
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