document.write( "Question 932584: A square has an area of 256 cm^2. If the same amount is removed from one dimension and added to the other, the resulting rectangle has an area 16 cm^2 less. Find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #566218 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "given:
\n" ); document.write( " area of a square is \"256cm%5E2\"\r
\n" ); document.write( "\n" ); document.write( "Let's represent each side as \"\"x\"\".
\n" ); document.write( "Let's represent the amount added and subtracted as \"\"y\"\".
\n" ); document.write( "if amount is removed from one dimension and added to the other, one side of rectangle will be:\"x-y\" and other side will be \"x%2By\"\r
\n" ); document.write( "\n" ); document.write( "then the measure of the side of square is \"sqrt%28256cm%5E2%29=+16cm\" , or the square is \"16cm\" by \"16cm\"\r
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\n" ); document.write( "The equation that can be set up is:\r
\n" ); document.write( "\n" ); document.write( "the area of a square is \"A=x%5E2=256cm%5E2\"\r
\n" ); document.write( "\n" ); document.write( "the area of a rectangle is \"A%5Br%5D=%28x-y%29%28x%2By%29\"\r
\n" ); document.write( "\n" ); document.write( "since the resulting rectangle has an area \"16cm%5E2\" less, we have:\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-16cm%5E2+=%28x%2By%29%28x-y%29+\".........solve for \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2-16cm%5E2+=x%5E2-y%5E2\"...............the \"x%5E2\" cancels out leaving us:\r
\n" ); document.write( "\n" ); document.write( "\"-16cm%5E2+=-y%5E2\".... divide both sides by \"-1\" \r
\n" ); document.write( "\n" ); document.write( "\"16cm%5E2+=y%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"y=4cm\"\r
\n" ); document.write( "\n" ); document.write( "so, the length of the rectangle is \"x%2By=16cm%2B4cm=20cm\" and
\n" ); document.write( "the width of the rectangle is \"x-y=16cm-4cm=12cm\"\r
\n" ); document.write( "\n" ); document.write( "Therefore we can solve this rectangle size as \"20cm\" by \"12cm\". \r
\n" ); document.write( "\n" ); document.write( "The area comes out to be \"A%5Br%5D=20cm%2A12cm=240cm%5E2\"\r
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