document.write( "Question 932538: A train leaves station M and travels west at 75 km/hr. Two hours later, a second train leaves the same station on a parallel track and travels west at 125 km/hr. Hor far from the station M will the faster train catch the slower one? \n" ); document.write( "
Algebra.Com's Answer #566188 by ptfile(81)![]() ![]() You can put this solution on YOUR website! Let t+2 = the time of the slower train \n" ); document.write( " t = the time of the faster train \n" ); document.write( " 75kph= the speed of the slower train \n" ); document.write( " 125kph= the speed of the faster train\r \n" ); document.write( "\n" ); document.write( "D=rt\r \n" ); document.write( "\n" ); document.write( "Slower train \n" ); document.write( "D=(75)(t+2) \n" ); document.write( "D=75t+150\r \n" ); document.write( "\n" ); document.write( "Faster train \n" ); document.write( "D=(125)(t) \n" ); document.write( "D=125t\r \n" ); document.write( "\n" ); document.write( "How far from the station M will the faster train catch the slower one? \n" ); document.write( "Distance of Slower train = Distance of faster train \n" ); document.write( " 75t+150 = 125t \n" ); document.write( " 150 = 50t \n" ); document.write( " 3 = t\r \n" ); document.write( "\n" ); document.write( "The time it took the faster train to catch up with the slower train is 3 hours.\r \n" ); document.write( "\n" ); document.write( "Check \n" ); document.write( "75(3)+150 = 125(3) \n" ); document.write( "225 + 150 = 375 \n" ); document.write( " 375 = 375\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |