document.write( "Question 925242: $5900 s invested, part of it at 12% and part of it at 8%. For a certain year, the total yield is $596.00. How? much was invested at each rate \n" ); document.write( "
Algebra.Com's Answer #566171 by ptfile(81)\"\" \"About 
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Let x = the amount invested at 12%
\n" ); document.write( " y = the amount invested at 8%\r
\n" ); document.write( "\n" ); document.write( "$5900 is invested.
\n" ); document.write( "x+y=5900\r
\n" ); document.write( "\n" ); document.write( "part of it at 12% and part of it at 8%. For a certain year, the total yield is $596.
\n" ); document.write( ".12x+.08y=596
\n" ); document.write( ".12x(-12.5)+.08y(-12.5)=596(-12.5)
\n" ); document.write( "-1.5x- y=-7450\r
\n" ); document.write( "\n" ); document.write( " x+ y= 5900
\n" ); document.write( "-1.5x- y=-7450
\n" ); document.write( " -.5x=-1550
\n" ); document.write( " x= 3100\r
\n" ); document.write( "\n" ); document.write( "Substitute x with $3100
\n" ); document.write( "$3100+y=5900
\n" ); document.write( " y=5900-3100
\n" ); document.write( " y=2800\r
\n" ); document.write( "\n" ); document.write( "Out of $5900, $3100 was invested at 12% and $2800 was invested at 8%.\r
\n" ); document.write( "\n" ); document.write( "Check
\n" ); document.write( ".12(3100)+.08(2800)=596
\n" ); document.write( " 372 + 224 =596
\n" ); document.write( " 596 =596
\n" ); document.write( " \n" ); document.write( "
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