document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=932046>Question 932046</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one number is twice another number.if 15 is substracted from both the numbers,the one of the new numbers become  trice that of new number.find the numbers<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #566115 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=566115\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> one number is twice another number.<BR>\n" );
document.write( "a = 2b <BR>\n" );
document.write( "if 15 is subtracted from both the numbers,the one of the new numbers become trice that of new number.<BR>\n" );
document.write( "a - 15 = 3(b - 15)<BR>\n" );
document.write( "a - 15 = 3b - 45<BR>\n" );
document.write( "a = 3b  - 45 + 15<BR>\n" );
document.write( "a = 3b - 30<BR>\n" );
document.write( "replace a with 2b<BR>\n" );
document.write( "2b = 3b - 30<BR>\n" );
document.write( "30 = 3b - 2b<BR>\n" );
document.write( "30 = b <BR>\n" );
document.write( ":<BR>\n" );
document.write( "one number (b) is 30 and the other number, obviously is 60\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );