document.write( "Question 78889: will someone check this for me please?\r
\n" ); document.write( "\n" ); document.write( "sqrt\"3x%2B9\"+6=0
\n" ); document.write( "sqrt\"3x%2B9\"=-6
\n" ); document.write( "(sqrt3x+9}}})^2=(-6)^2
\n" ); document.write( "3x+9=36
\n" ); document.write( "3x=27
\n" ); document.write( "x=27
\n" ); document.write( "

Algebra.Com's Answer #56609 by tutor_paul(519)\"\" \"About 
You can put this solution on YOUR website!
You did fine until the very last step...
\n" ); document.write( "\"3x=27\", so:
\n" ); document.write( "\"x=9\"
\n" ); document.write( "Good Job!
\n" ); document.write( "tutor_paul@yahoo.com
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