document.write( "Question 932280: Two cyclists leave a city at the same time, one going east and the other going west. The west-bound cyclist bikes 4 mph faster than the east-bound cyclist. After 5 hours they are 200 miles apart. How fast is the east-bound cyclist going? \n" ); document.write( "
Algebra.Com's Answer #566083 by TimothyLamb(4379)\"\" \"About 
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x = speed east biker
\n" ); document.write( "y = speed west biker = x + 4
\n" ); document.write( "---
\n" ); document.write( "relative speed of the bikers:
\n" ); document.write( "x + y
\n" ); document.write( "x + x + 4
\n" ); document.write( "2x + 4
\n" ); document.write( "---
\n" ); document.write( "s = d/t
\n" ); document.write( "2x + 4 = 200/5
\n" ); document.write( "2x = 200/5 - 4
\n" ); document.write( "x = (200/5 - 4)/2
\n" ); document.write( "x = 18
\n" ); document.write( "y = x + 4
\n" ); document.write( "y = 18 + 4
\n" ); document.write( "y = 22
\n" ); document.write( "---
\n" ); document.write( "answer:
\n" ); document.write( "x = speed east biker = 18 mph
\n" ); document.write( "y = speed west biker = 22 mph
\n" ); document.write( "---
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