document.write( "Question 931952: What is the amplitude, period and phase shift of the following function: \r
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document.write( "y=1+COS (3x + pi/2) \r
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document.write( "How would I graph one complete period? \n" );
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Algebra.Com's Answer #566067 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! What is the amplitude, period and phase shift of the following function: \n" ); document.write( "y=1+COS (3x + pi/2) \n" ); document.write( "How would I graph one complete period? \n" ); document.write( "*** \n" ); document.write( "Equation for cos function: y=Acos(Bx-C), A=amplitude, period=2π/B, Phase shift=C/B. \n" ); document.write( "For given cos function: \n" ); document.write( "A=1 \n" ); document.write( "B=3 \n" ); document.write( "Period=2π/B=2π/3 \n" ); document.write( "1/4 period=(2π/3)/4=2π/12=π/6 \n" ); document.write( "C=π/2 \n" ); document.write( "Phase shift:C/B=(π/2)/3=π/6 (to the left) \n" ); document.write( ".. \n" ); document.write( "Determine coordinates: \n" ); document.write( "set up inequality of cos function for one period \n" ); document.write( "0 ≤ (3x+π/2) ≤ 2π/3 \n" ); document.write( "subtract π/2 from each term \n" ); document.write( "-π/2 ≤ 3x ≤ π/6= \n" ); document.write( "divide each term by 3 \n" ); document.write( "-π/6 ≤ x ≤ π/2 \n" ); document.write( ".. \n" ); document.write( "coordinates of graph: \n" ); document.write( "(-π/6,2),(0,1),(π/6,0),(2π/6,1),(3π/6,2) \n" ); document.write( "or \n" ); document.write( "(-π/6,2),(0,1),(π/6,0),(π/3,1),(π/2,2) \n" ); document.write( " \n" ); document.write( " |