document.write( "Question 78896: please help me simplify this problem?\r
\n" ); document.write( "\n" ); document.write( "sqrt\"75a%5E2\"/sqrt\"5\"
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Algebra.Com's Answer #56606 by tutor_paul(519)\"\" \"About 
You can put this solution on YOUR website!
\"%28sqrt%2875a%5E2%29%29%2F%28sqrt%285%29%29\"
\n" ); document.write( "The first step is to recognize that \"sqrt%28a%5E2%29=a\", so you can rewrite it as:
\n" ); document.write( "\"%28a%2Asqrt%2875%29%29%2F%28sqrt%285%29%29\"
\n" ); document.write( "Now, you need to see that \"75=5%2A4%2A4\", so you can also pull out a 4 from under the radical:
\n" ); document.write( "\"%284a%2Asqrt%285%29%29%2F%28sqrt%285%29%29\"
\n" ); document.write( "Finally, cancel out the \"sqrt%285%29\" term, and you are done:
\n" ); document.write( "\"4a\"
\n" ); document.write( "Good Luck,
\n" ); document.write( "tutor_paul@yahoo.com
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