document.write( "Question 932172: what is the solution to 3^(2x)=125? \n" ); document.write( "

Algebra.Com's Answer #566021 by MathLover1(20850) $\"\"$ $\"About$

You can put this solution on YOUR website!

\n" ); document.write( " $\"3%5E%282x%29=125\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"3%5E%282x%29=5%5E3\"$ ...use log\r
\n" ); document.write( "\n" ); document.write( " $\"log%283%5E%282x%29%29=log%285%5E3%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"%282x%29log%283%29=3log%285%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x=%283%2F2%29log%285%29%2Flog%283%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x=%283%2F2%29log%285%29%2Flog%283%29\"$ ...in base $\"10\"$ , $\"log%285%29=0.69897\"$ and $\"log%283%29=0.4771212547\"$ approximately (because exact value is to long)\r
\n" ); document.write( "\n" ); document.write( " $\"x=%281.5%29%280.69897%2F0.4771212547%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x=%281.5%29%281.464973512%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x=2.197460268\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x=2.197460268\"$ \r
\n" ); document.write( "\n" ); document.write( "check:\r
\n" ); document.write( "\n" ); document.write( " $\"3%5E%282%2A2.197460268%29=124.999996\"$ , rounded to whole number it is $\"125\"$ \n" ); document.write( "

\n" );