document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=78902>Question 78902</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/020132458X/algebrahomeworkh>Algebra I</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> (6ab^2/35b)(42a/18ab) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #56596 by </B><A HREF=/tutors/aboutme.mpl?userid=mathdoc314><B>mathdoc314(58)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mathdoc314><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=56596\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I really think it is wrong to submit a question without any words\r<BR>\n" );
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document.write( "The answer is (6ab^2/35b) (42a/18ab)\r<BR>\n" );
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document.write( "Is that OK?\r<BR>\n" );
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document.write( "Oh, you want me to simplify it?\r<BR>\n" );
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document.write( "Why didn't you say so?\r<BR>\n" );
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document.write( "So in the first term which is (6ab^2/35b) i see that b can be canceled since the same factor b is in the top and the bottom\r<BR>\n" );
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document.write( "6ab/35\r<BR>\n" );
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document.write( "In the secont term which is 42a/18ab I see a can be canceled since the factor a is in the numerator and denominator.  Also 42 and 18 are divisible by 6 \r<BR>\n" );
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document.write( "7/3b\r<BR>\n" );
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document.write( "So we are multiplying (6ab/35) * (7/3b)\r<BR>\n" );
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document.write( "The basic idea in this kid of problem is: (A/B)*(C/D) is just (A*C)/(B*D)\r<BR>\n" );
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document.write( "so that is (42ab / 105 b)\r<BR>\n" );
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document.write( "This can be condensed some more by canceling 7 from top and bottom, and b\r<BR>\n" );
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document.write( "I end up with 2a / 5\r<BR>\n" );
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document.write( "There is not really a way to check this kind of problem except to do it over again, preferably by antoher person doing the operations in a different order\r<BR>\n" );
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document.write( "(6ab^2/35b) (42a/18ab)\r<BR>\n" );
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document.write( "2*3*2*3*7*a*a*b*b / 5*7*b*2*3*3*a*b \r<BR>\n" );
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document.write( "cancel out most of that\r<BR>\n" );
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document.write( "This time I also get 2 a / 5 which luckily confirms the first response (I had to change them each three times to make this work)\r<BR>\n" );
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