document.write( "Question 932100: how many liters of a 20% alcohol should be added to 6 liters of a 40% alcohol solution so that the mixture is a 35% alcohol solution? \n" ); document.write( "
Algebra.Com's Answer #565959 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! ow many liters of a 20% alcohol should be added to 6 liters of a 40% alcohol solution so that the mixture is a 35% alcohol solution?\r \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "Make this chart:\r\n" ); document.write( "\r\n" ); document.write( " | liters | percent as | liters of |\r\n" ); document.write( " | of liquid | a decimal | pure alcohol |\r\n" ); document.write( "-------------------------|-----------|------------|--------------|\r\n" ); document.write( " weaker solution | | | |\r\n" ); document.write( " stronger solution | | | | \r\n" ); document.write( "-------------------------|-----------|------------|--------------|\r\n" ); document.write( "medium strength solution | | | | \r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Let x be the answer, x = no. of liters of weaker solution.\r\n" ); document.write( "And fill in what is given:\r\n" ); document.write( "\r\n" ); document.write( " | liters | percent as | liters of |\r\n" ); document.write( " | of liquid | a decimal | pure alcohol |\r\n" ); document.write( "-------------------------|-----------|------------|--------------|\r\n" ); document.write( " weaker solution | x | 0.20 | |\r\n" ); document.write( " stronger solution | 6 | 0.40 | | \r\n" ); document.write( "-------------------------|-----------|------------|--------------|\r\n" ); document.write( "medium strength solution | | 0.35 | | \r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Now we get the number of liters of liquid by adding x and 6, getting x+6,\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " | liters | percent as | liters of |\r\n" ); document.write( " | of liquid | a decimal | pure alcohol |\r\n" ); document.write( "-------------------------|-----------|------------|--------------|\r\n" ); document.write( " weaker solution | x | 0.20 | |\r\n" ); document.write( " stronger solution | 6 | 0.40 | | \r\n" ); document.write( "-------------------------|-----------|------------|--------------|\r\n" ); document.write( "medium strength solution | x+6 | 0.35 | | \r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Next we get the number of liters of pure alcohol in each by multiplying\r\n" ); document.write( "the number of liters of liquid by the percentage of each:\r\n" ); document.write( "\r\n" ); document.write( " | liters | percent as | liters of |\r\n" ); document.write( " | of liquid | a decimal | pure alcohol |\r\n" ); document.write( "-------------------------|-----------|------------|--------------|\r\n" ); document.write( " weaker solution | x | 0.20 | 0.20x |\r\n" ); document.write( " stronger solution | 6 | 0.40 | 0.40(6) | \r\n" ); document.write( "-------------------------|-----------|------------|--------------|\r\n" ); document.write( "medium strength solution | x+6 | 0.35 | 0.35(x+6) |\r\n" ); document.write( "\r\n" ); document.write( "The equation comes from:\r\n" ); document.write( "\r\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |