document.write( "Question 932100: how many liters of a 20% alcohol should be added to 6 liters of a 40% alcohol solution so that the mixture is a 35% alcohol solution? \n" ); document.write( "
Algebra.Com's Answer #565935 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! x the amount of the 20% solution \n" ); document.write( ".20x + .40(6L) = .35(6L + x) \n" ); document.write( " .05(6L)/.15 = x = 2L, the amount of the 20% solution \n" ); document.write( " \n" ); document.write( " |