document.write( "Question 931935: I need help on this problem
\n" ); document.write( "Two pipes together can fill a tank in 6 hours. Pipe 1 alone can fill the tank in 10 hours. In how much time can pipe 2 fill the tank alone?\r
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Algebra.Com's Answer #565885 by ankor@dixie-net.com(22740)\"\" \"About 
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Two pipes together can fill a tank in 6 hours.
\n" ); document.write( " Pipe 1 alone can fill the tank in 10 hours.
\n" ); document.write( " In how much time can pipe 2 fill the tank alone?
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\n" ); document.write( "let x = time required by pipe 2 to fill the tank alone
\n" ); document.write( "let a full tank = 1
\n" ); document.write( "each pipe will do a fraction of the job, the two fractions add up to 1
\n" ); document.write( "\"6%2F10\" + \"6%2Fx\" = 1
\n" ); document.write( "multiply by 10x, cancel the denominators and you have
\n" ); document.write( "6x + 10(6) = 10x
\n" ); document.write( "6x + 60 = 10x
\n" ); document.write( "60 = 10x - 6x
\n" ); document.write( "60 = 4x
\n" ); document.write( "x = 60/4
\n" ); document.write( "x = 15 min for pipe 2 to fill it alone
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\n" ); document.write( "confirm this
\n" ); document.write( " \"6%2F10\" + \"6%2F15\" = 1
\n" ); document.write( ".6 + .4 = 1\r
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