document.write( "Question 931935: I need help on this problem
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document.write( "Two pipes together can fill a tank in 6 hours. Pipe 1 alone can fill the tank in 10 hours. In how much time can pipe 2 fill the tank alone?\r
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Algebra.Com's Answer #565885 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! Two pipes together can fill a tank in 6 hours. \n" ); document.write( " Pipe 1 alone can fill the tank in 10 hours. \n" ); document.write( " In how much time can pipe 2 fill the tank alone? \n" ); document.write( ": \n" ); document.write( "let x = time required by pipe 2 to fill the tank alone \n" ); document.write( "let a full tank = 1 \n" ); document.write( "each pipe will do a fraction of the job, the two fractions add up to 1 \n" ); document.write( " \n" ); document.write( "multiply by 10x, cancel the denominators and you have \n" ); document.write( "6x + 10(6) = 10x \n" ); document.write( "6x + 60 = 10x \n" ); document.write( "60 = 10x - 6x \n" ); document.write( "60 = 4x \n" ); document.write( "x = 60/4 \n" ); document.write( "x = 15 min for pipe 2 to fill it alone \n" ); document.write( ": \n" ); document.write( "; \n" ); document.write( "confirm this \n" ); document.write( " \n" ); document.write( ".6 + .4 = 1\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |