document.write( "Question 930962: Given cos(t)=-3/4 with pi < t < {3pi}/{2}, find the values of the following trigonometric functions. \r
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\n" ); document.write( "cos(2t) = \r
\n" ); document.write( "\n" ); document.write( "sin(2t) = \r
\n" ); document.write( "\n" ); document.write( "cos(t/2)= \r
\n" ); document.write( "\n" ); document.write( "sin(t/2) =
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Algebra.Com's Answer #565840 by lwsshak3(11628)\"\" \"About 
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Given cos(t)=-3/4 with pi < t < {3pi}/{2}, find the values of the following trigonometric functions.
\n" ); document.write( "Note: Give exact answers.
\n" ); document.write( "cos(2t) =
\n" ); document.write( "sin(2t) =
\n" ); document.write( "cos(t/2)=
\n" ); document.write( "sin(t/2) =
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\n" ); document.write( "reference angle t is in quadrant III where sin<0, cos<0
\n" ); document.write( "cost=-3/4
\n" ); document.write( "sint=-√(1-cos^2(t))=-√(1-9/16)=-√(7/16)=-√7/4
\n" ); document.write( "..
\n" ); document.write( "cos(2t)=1-2sin^2(t)=1-2(7/16)=1-14/16=2/16=1/8
\n" ); document.write( "sin(2t)=2sintcost=2*-(√7/4)*-(3/4)=6√7/16
\n" ); document.write( "cos(t/2)=-√((1+cost)/2)=-√((1-(3/4))/2)=-√(1/8)=-1/√8=-√8/8
\n" ); document.write( "sin(t/2)=√((1-cost)/2)=√((1+(3/4))/2)=√(7/8) \n" ); document.write( "
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