document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=931820>Question 931820</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a home has a triangular backyard. the second angle of the triangle is twice as large as the first. The third angle of the triangle is 24 degrees more than the first. Find the third angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #565833 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=565833\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x the first angle<BR>\n" );
document.write( "x + 2x + (x+24) = 180° <BR>\n" );
document.write( "4x = 156<BR>\n" );
document.write( "x = 39° <BR>\n" );
document.write( ".....<BR>\n" );
document.write( "3rd angle  is 63°  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=39%2B24 ALIGN=MIDDLE  ALT=\"39%2B24\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "And...checking<BR>\n" );
document.write( "39°  + 78°  + 63°  = 180°  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );