document.write( "Question 931785: A normal population has a mean of 66 and a standard deviation of 4. You select a sample of 48.
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document.write( "Compute the probability the sample mean is: (Round z values to 2 decimal places and final answers to 4 decimal places.)
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document.write( "(a) Less than 65.\r
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document.write( " Probability \r
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document.write( "(b) Between 65 and 67.\r
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document.write( "(c) Between 67 and 68.\r
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document.write( "(d) Greater than 68.
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document.write( " Probability
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Algebra.Com's Answer #565816 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! mean of 66 and a standard deviation of 4. \n" ); document.write( "n = 48, \n" ); document.write( "P(x < 65) = P(z <-1/.58) = normalcdf(-100, -1.72) \n" ); document.write( "P(65 < x <67) = P(-1.72 < z < 1.72) = normalcdf(-1.72, 1.72) \n" ); document.write( "P( 67< x < 68) = P(1.72 < z < 3.45)=normalcdf(1.72, 3.45) \n" ); document.write( "P(x > 68) = P(z > 3.45) = normalcdf(3.45, 100) \n" ); document.write( " |