document.write( "Question 78866: Greta is making a cube with a surface area of 24 square feet.\r
\n" ); document.write( "\n" ); document.write( "If Greta triples the dimensions of the cube, what will the new surface area be?
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Algebra.Com's Answer #56578 by jim_thompson5910(35256)\"\" \"About 
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We know the surface area of a cube to be\r
\n" ); document.write( "\n" ); document.write( "\"S=6x%5E2\" (since its base*height*number of faces)\r
\n" ); document.write( "\n" ); document.write( "Now plug in 24 into the original equation\r
\n" ); document.write( "\n" ); document.write( "\"24=6x%5E2\"\r
\n" ); document.write( "\n" ); document.write( "So lets solve for x\r
\n" ); document.write( "\n" ); document.write( "\"x%5E2=4\" Divide both sides by 6\r
\n" ); document.write( "\n" ); document.write( "\"x=2\" Take the square root of both sides\r
\n" ); document.write( "\n" ); document.write( "So our original dimensions are 2 feet by 2 feet\r
\n" ); document.write( "\n" ); document.write( "Now if we triple the original dimensions we get\r
\n" ); document.write( "\n" ); document.write( "2*3=6\r
\n" ); document.write( "\n" ); document.write( "So plug 6 into x\r
\n" ); document.write( "\n" ); document.write( "\"S=6%286%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"S=6%2A36\"\r
\n" ); document.write( "\n" ); document.write( "\"S=216\"\r
\n" ); document.write( "\n" ); document.write( "So the new surface area is 216 sq ft
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